13y^2+40=1

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Solution for 13y^2+40=1 equation: 



13y^2+40=1

We move all terms to the left:

13y^2+40-(1)=0

We add all the numbers together, and all the variables

13y^2+39=0

a = 13; b = 0; c = +39;
Δ = b2-4ac
Δ = 02-4·13·39
Δ = -2028
Delta is less than zero, so there is no solution for the equation

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